In this final post of a 4-part series, I have a TSQL implementation of the Damerau-Levenshtein algorithm, and describe some of the testing to ensure the optimizations didn’t introduce errors in the results. Previous posts covered Levenshtein in C#, Levenshtein in TSQL, and Damerau-Levanshtein in C#.
This TSQL implementation takes the Levenshtein implementation from the previous post, and adds the additional logic needed to support Damerau’s transposition handling. The way it is implemented is like that done in the C# implementation in the previous post. You can check out those earlier posts for more details. Using the C# implementation in a CLR will give the fastest results in SQL Server. But if, for some reason, you can’t enable CLR user functions on your server, this TSQL implementation is a viable alternative. The version here is faster than the other versions I’ve seen on the internet.
While working on the code in these four posts, I did a fair amount of testing to help ensure that the optimizations did not mess up the results in subtle ways. Many of the optimizations depart from the standard algorithms with tricks and shortcuts to reduce the work performed. There’s always the chance that changes like that will muck up the results. To test, I made a basic implementation of Levenshtein and Damerau-Levenshtein. I also grabbed second implementations from the internet and compared results for all pairings of every permutation of 1 to 7 character words using a small character set (about 11,000,000 word pairs). With those “truth” functions verified, I could use them to do the same verification of the algorithms I was working on.
-- Computes and returns the Damerau-Levenshtein edit distance between two strings,
-- i.e. the number of insertion, deletion, substitution, and transposition edits
-- required to transform one string to the other. This value will be >= 0, where
-- 0 indicates identical strings. Comparisons use the case-sensitivity configured
-- in SQL Server (case-insensitive by default). This algorithm is basically the
-- Levenshtein algorithm with a modification that considers transposition of two
-- adjacent characters as a single edit.
-- See http://en.wikipedia.org/wiki/Damerau%E2%80%93Levenshtein_distance
-- Note that this uses Sten Hjelmqvist's "Fast, memory efficient" algorithm, described
-- at http://www.codeproject.com/Articles/13525/Fast-memory-efficient-Levenshtein-algorithm.
-- This version differs by including some optimizations, and extending it to the Damerau-
-- Levenshtein algorithm.
-- Note that this is the simpler and faster optimal string alignment (aka restricted edit) distance
-- that difers slightly from the full Damerau-Levenshtein algorithm by imposing the restriction
-- that no substring is edited more than once. So for example, "CA" to "ABC" has an edit distance
-- of 2 by a complete application of Damerau-Levenshtein, but a distance of 3 by this method that
-- uses the optimal string alignment algorithm. See wikipedia article for more detail on this
-- @s - String being compared for distance.
-- @t - String being compared against other string.
-- @max - Maximum distance allowed, or NULL if no maximum is desired. Returns NULL if distance will exceed @max.
-- returns int edit distance, >= 0 representing the number of edits required to transform one string to the other.
CREATE FUNCTION [dbo].[DamLev](
@s nvarchar(4000) , @t nvarchar(4000) , @max int ) RETURNS int WITH SCHEMABINDING AS BEGIN DECLARE @distance int = 0 -- return variable , @v0 nvarchar(4000)-- running scratchpad for storing computed distances , @v2 nvarchar(4000)-- running scratchpad for storing previous column's computed distances , @start int = 1 -- index (1 based) of first non-matching character between the two string , @i int, @j int -- loop counters: i for s string and j for t string , @diag int -- distance in cell diagonally above and left if we were using an m by n matrix , @left int -- distance in cell to the left if we were using an m by n matrix , @nextTransCost int-- transposition base cost for next iteration , @thisTransCost int-- transposition base cost (2 distant along diagonal) for current iteration , @sChar nchar -- character at index i from s string , @tChar nchar -- character at index j from t string , @thisJ int -- temporary storage of @j to allow SELECT combining , @jOffset int -- offset used to calculate starting value for j loop , @jEnd int -- ending value for j loop (stopping point for processing a column) -- get input string lengths including any trailing spaces (which SQL Server would otherwise ignore) , @sLen int = datalength(@s) / datalength(left(left(@s, 1) + '.', 1)) -- length of smaller string , @tLen int = datalength(@t) / datalength(left(left(@t, 1) + '.', 1)) -- length of larger string , @lenDiff int -- difference in length between the two strings -- if strings of different lengths, ensure shorter string is in s. This can result in a little -- faster speed by spending more time spinning just the inner loop during the main processing. IF (@sLen > @tLen) BEGIN SELECT @v0 = @s, @i = @sLen -- temporarily use v0 for swap SELECT @s = @t, @sLen = @tLen SELECT @t = @v0, @tLen = @i END SELECT @max = ISNULL(@max, @tLen) , @lenDiff = @tLen - @sLen IF @lenDiff > @max RETURN NULL -- suffix common to both strings can be ignored WHILE(@sLen > 0 AND SUBSTRING(@s, @sLen, 1) = SUBSTRING(@t, @tLen, 1)) SELECT @sLen = @sLen - 1, @tLen = @tLen - 1 IF (@sLen = 0) RETURN @tLen -- prefix common to both strings can be ignored WHILE (@start < @sLen AND SUBSTRING(@s, @start, 1) = SUBSTRING(@t, @start, 1)) SELECT @start = @start + 1 IF (@start > 1) BEGIN SELECT @sLen = @sLen - (@start - 1) , @tLen = @tLen - (@start - 1) -- if all of shorter string matches prefix and/or suffix of longer string, then -- edit distance is just the delete of additional characters present in longer string IF (@sLen <= 0) RETURN @tLen SELECT @s = SUBSTRING(@s, @start, @sLen) , @t = SUBSTRING(@t, @start, @tLen) END -- initialize v0 array of distances SELECT @v0 = '', @j = 1 WHILE (@j <= @tLen) BEGIN SELECT @v0 = @v0 + NCHAR(CASE WHEN @j > @max THEN @max ELSE @j END) SELECT @j = @j + 1 END SELECT @v2 = @v0 -- copy...doesn't matter what's in v2, just need to initialize its size , @jOffset = @max - @lenDiff , @i = 1 WHILE (@i <= @sLen) BEGIN SELECT @distance = @i , @diag = @i - 1 , @sChar = SUBSTRING(@s, @i, 1) -- no need to look beyond window of upper left diagonal (@i) + @max cells -- and the lower right diagonal (@i - @lenDiff) - @max cells , @j = CASE WHEN @i <= @jOffset THEN 1 ELSE @i - @jOffset END , @jEnd = CASE WHEN @i + @max >= @tLen THEN @tLen ELSE @i + @max END , @thisTransCost = 0 WHILE (@j <= @jEnd) BEGIN -- at this point, @distance holds the previous value (the cell above if we were using an m by n matrix) SELECT @nextTransCost = UNICODE(SUBSTRING(@v2, @j, 1)) , @v2 = STUFF(@v2, @j, 1, NCHAR(@diag)) , @tChar = SUBSTRING(@t, @j, 1) , @left = UNICODE(SUBSTRING(@v0, @j, 1)) , @thisJ = @j SELECT @distance = CASE WHEN @diag < @left AND @diag < @distance THEN @diag --substitution WHEN @left < @distance THEN @left -- insertion ELSE @distance -- deletion END SELECT @distance = CASE WHEN (@sChar = @tChar) THEN @diag -- no change (characters match) WHEN @i <> 1 AND @j <> 1 AND @tChar = SUBSTRING(@s, @i - 1, 1) AND @thisTransCost < @distance AND @sChar = SUBSTRING(@t, @j - 1, 1) THEN 1 + @thisTransCost -- transposition ELSE 1 + @distance END SELECT @v0 = STUFF(@v0, @thisJ, 1, NCHAR(@distance)) , @diag = @left , @thisTransCost = @nextTransCost , @j = case when (@distance > @max) AND (@thisJ = @i + @lenDiff) then @jEnd + 2 else @thisJ + 1 end END SELECT @i = CASE WHEN @j > @jEnd + 1 THEN @sLen + 1 ELSE @i + 1 END END RETURN CASE WHEN @distance <= @max THEN @distance ELSE NULL END END